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Open in AppSolutionSuggest Corrections7Similar questionsQ. Given the condition 56<12x−12y<32, find one possible value of x−y?Q. If 2x+y=9 and 3x−y=6 then find the value of 6x+y=7x−y+312x+y=13x−yQ. Find the value of x and y -x−3y=3x−1=2x−yQ. If 1+cos2x+cos4x+cos6x=ycosxcos2xcos3x, then find the value of MoreRelated VideosQuestionsMATHEMATICSWatch in AppExplore moreVariable on Both SidesStandard VIII Mathematics
a= 5/2,2,3/2,1,1/2. At the origin, the curve y = x5/2 has the curvature 0 (since it is best approximated by the parabola y = kx2/2 with k = 0); the curve y = x2/2 is the parabola with k = 1; the curve y = x3/2/(3/2) has the If P 6= P ′ then all points equidistant to them are situated on the line perpendic-Midpoint of diagonal BD is ( 4+3 2, 5+y 2) ⇒(7 2, 5+y 2) Since the diagonals of a parallelogram bisect each other, the midpoints of AC and BD are the same. ∴ x+1 2 = 7 2 and 4= 5+y 2. ⇒ x+1= 7 and 5+y =8. ⇒ x= 6 and y= 3. Mathematics. NCERT Textbook. Standard X.. 408 405 191 173 57 70 194 240